Find the equation of the plane passing through the point `( 1, 3, 2)`and perpendicular to each of the planes `x + 2y + 3z = 5`and `3x + 3y + z = 0`.

Explanation

To find the equation of the plane passing through the point \( (1, 3, 2) \) and perpendicular to the planes given by the equations \( x + 2y + 3z = 5 \) and \( 3x + 3y + z = 0 \), we can follow these steps:

### Step 1: Identify the normal vectors of the given planes
The normal vector of the first plane \( x + 2y + 3z = 5 \) is given by the coefficients of \( x, y, z \):
\[ \mathbf{n_1} = (1, 2, 3) \]
The normal vector of the second plane \( 3x + 3y + z = 0 \) is:
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