When anisole is heated with HI , the product is :

Options

A. Phenyl iodide and methyl iodide
B. Phenol and methanol
C. Phenyl iodide and methanol
D. Methyl iodide and phenol

Answer

To determine the product formed when anisole is heated with HI, we can follow these steps:

### Step 1: Identify the structure of anisole
Anisole is an aromatic ether with the formula C6H5OCH3. It consists of a phenyl group (C6H5) attached to a methoxy group (OCH3).

**Hint:** Remember that anisole is an aromatic compound with a methoxy group.

### Step 2: Understand the reaction with HI
When anisole is heated with hydroiodic acid (HI), the HI dissociates into H⁺ and I⁻ ions. The H⁺ ion can protonate the oxygen atom in the methoxy group of anisole.

**Hint:** Hydroiodic acid is a strong acid that can donate protons (H⁺).

### Step 3: Formation of the oxonium ion
The oxygen atom in the methoxy group has lone pairs and can donate one of these pairs to bond with the H⁺ ion, forming a methyl phenyl oxonium ion. This results in a positively charged oxygen atom.

**Hint:** Look for the formation of an oxonium ion when the oxygen atom accepts a proton.

### Step 4: Nucleophilic attack by iodide ion
The I⁻ ion, which is negatively charged, will now attack the positively charged oxonium ion. The I⁻ will replace the methoxy group, leading to the formation of methyl iodide (CH3I) and phenol (C6H5OH).

**Hint:** The negatively charged iodide ion acts as a nucleophile and attacks the positively charged oxygen.

### Step 5: Final products
The final products of the reaction are phenol and methyl iodide.

**Hint:** Always check for the stability of the products formed in a reaction.

### Conclusion
When anisole is heated with HI, the products formed are phenol and methyl iodide.

**Final Answer:** Phenol and methyl iodide.