The product of the reaction of ethyl bromide with dry silver oxide is the functional isomer of:

Options

A. A primary alcohol
B. A secondary alcohol
C. A tertiary alcohol
D. All of the above

Answer

To solve the question regarding the product of the reaction of ethyl bromide with dry silver oxide and its functional isomer, we can follow these steps:

### Step 1: Understand the Reactants
- Ethyl bromide (C2H5Br) is an alkyl halide.
- Dry silver oxide (Ag2O) is a reagent that can facilitate the formation of ethers from alkyl halides.

### Step 2: Reaction Mechanism
- When ethyl bromide reacts with dry silver oxide, a nucleophilic substitution reaction occurs.
- The bromine atom in ethyl bromide is replaced by an alkoxy group (in this case, the ethyl group), leading to the formation of diethyl ether (C2H5-O-C2H5).

### Step 3: Identify the Product
- The product formed is diethyl ether (C4H10O), which has the molecular formula C4H10O.

### Step 4: Determine Functional Isomers
- Functional isomers have the same molecular formula but different functional groups.
- For C4H10O, we can consider the following alcohols:
- **1-Butanol (a primary alcohol)**: CH3-CH2-CH2-CH2-OH
- **2-Butanol (a secondary alcohol)**: CH3-CH(OH)-CH2-CH3
- **Tert-Butanol (a tertiary alcohol)**: (CH3)3C-OH

### Step 5: Confirm Molecular Formula
- All these alcohols have the same molecular formula (C4H10O) as diethyl ether.
- Therefore, diethyl ether is a functional isomer of these alcohols.

### Conclusion
- The product of the reaction of ethyl bromide with dry silver oxide (diethyl ether) is a functional isomer of 1-butanol, 2-butanol, and tert-butanol.

### Final Answer
- The correct answer is that the product is a functional isomer of all of the above alcohols.

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