`C_(6) H_(5) N_(2) Cl + "HBF"_(4) overset(Delta)(rarr) C_(6)H_(5)F + N_(2) + BF_(3)` . The reaction is called

Options

A. Balzschiemann reaction
B. Gattermann reaction
C. Sandmeyer’s reaction
D. Swarts reaction

Answer

To determine the name of the reaction given in the question, we will analyze the provided chemical equation step by step.

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
The reaction provided is:
\[ C_6H_5N_2Cl + HBF_4 \xrightarrow{\Delta} C_6H_5F + N_2 + BF_3 \]
Here, the reactants are benzenediazonium chloride (\(C_6H_5N_2Cl\)) and tetrafluoroboric acid (\(HBF_4\)). The products are fluorobenzene (\(C_6H_5F\)), nitrogen gas (\(N_2\)), and boron trifluoride (\(BF_3\)).

2. **Recognize the Type of Reaction:**
This reaction involves the conversion of a diazonium salt into a fluorinated aromatic compound. The diazonium salt is formed from aniline and nitrous acid, and it undergoes a substitution reaction where the diazonium group is replaced by a fluorine atom.

3. **Understand the Mechanism:**
The mechanism involves the formation of a diazonium tetrafluoroborate intermediate when \(C_6H_5N_2Cl\) reacts with \(HBF_4\). Upon heating, this intermediate decomposes to release nitrogen gas and boron trifluoride, while fluorobenzene is formed.

4. **Name the Reaction:**
The reaction described is known as the **Bieschmann Reaction**. This is a specific type of reaction where a diazonium salt is converted into a fluorinated aromatic compound using tetrafluoroboric acid.

### Final Answer:
The reaction is called the **Bieschmann Reaction**.

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