When anisole is heated with HI , the product is :

Options

A. Phenyl iodide and methyl iodide
B. Phenol and methanol
C. Phenyl iodide and methanol
D. Methyl iodide and phenol

Answer

To determine the product formed when anisole is heated with HI, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Anisole is an ether with the formula C6H5OCH3 (phenyl methyl ether).
- HI is hydroiodic acid, which is a strong acid.

2. **Protonation of Anisole**:
- When anisole is heated with HI, the oxygen atom in the anisole molecule can be protonated by the H+ from HI. This forms an oxonium ion (OCH3^+).

3. **Formation of the Oxonium Ion**:
- The protonation leads to the formation of an oxonium ion where the oxygen carries a positive charge. The structure can be represented as:
\[ \text{OCH}_3^+ \]
- This ion is more reactive and can undergo further reactions.

4. **Nucleophilic Attack by Iodide Ion**:
- The iodide ion (I^-) from HI can now act as a nucleophile. It can attack the carbon atom of the methyl group (CH3) attached to the oxygen in the oxonium ion.
- This results in the cleavage of the C-O bond.

5. **Formation of Products**:
- The nucleophilic attack leads to the formation of two products:
- Phenol (C6H5OH) from the aromatic part of anisole.
- Methyl iodide (CH3I) from the methyl group.

6. **Final Products**:
- Therefore, the final products when anisole is heated with HI are phenol and methyl iodide.

### Conclusion:
The product formed when anisole is heated with HI is phenol (C6H5OH) and methyl iodide (CH3I).