Pyrolysis of acetone gives `CH_(2)=C=O` called `:`

Options

A. Methylene oxide
B. Methyl carbon monoxide
C. Ketene
D. Methone

Answer

To solve the question regarding the pyrolysis of acetone and the product formed, we will follow these steps:

### Step 1: Understand Pyrolysis
Pyrolysis is a thermochemical treatment where organic materials are heated to high temperatures in the absence of oxygen. This process breaks down the organic compounds into smaller molecules, which can be gases, liquids, or solids.

**Hint:** Remember that pyrolysis occurs without oxygen and involves high temperatures.

### Step 2: Identify the Structure of Acetone
Acetone has the chemical formula \( \text{CH}_3\text{COCH}_3 \). It consists of a carbonyl group (C=O) flanked by two methyl groups (CH3).

**Hint:** Acetone is a simple ketone with two methyl groups attached to a carbonyl carbon.

### Step 3: Analyze the Pyrolysis of Acetone
When acetone undergoes pyrolysis, it breaks down into smaller molecules. The main product formed from the pyrolysis of acetone is a compound with the structure \( \text{CH}_2=C=O \).

**Hint:** Focus on the changes in the structure after heating; the carbonyl group can rearrange to form a new compound.

### Step 4: Identify the Product
The compound \( \text{CH}_2=C=O \) is known as **ketene**. Ketene has a unique structure with a double bond between two carbon atoms and a double bond between one of those carbons and an oxygen atom. It can also be referred to as **ethenone**.

**Hint:** Look for the presence of double bonds in the product to help identify it as ketene.

### Step 5: Conclusion
Thus, the product of the pyrolysis of acetone is **ketene** (or ethenone).

**Final Answer:** Ketene (Ethenone)

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