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If the percentage errors in measuring ma...

If the percentage errors in measuring mass and velocity of a particle are respectively `2%` and `1%` percentage error in measuring its kinetic energy isp

A

`1%`

B

`2%`

C

`4%`

D

`8%`

Text Solution

AI Generated Solution

The correct Answer is:
To find the percentage error in measuring the kinetic energy of a particle given the percentage errors in mass and velocity, we can follow these steps: ### Step 1: Understand the formula for kinetic energy The kinetic energy (KE) of a particle is given by the formula: \[ KE = \frac{1}{2} mv^2 \] ### Step 2: Identify the percentage errors We are given: - Percentage error in mass (\( \Delta m/m \)) = 2% - Percentage error in velocity (\( \Delta v/v \)) = 1% ### Step 3: Use the formula for percentage error in kinetic energy The formula for the percentage error in kinetic energy is derived from the kinetic energy formula: \[ \frac{\Delta KE}{KE} = \frac{\Delta m}{m} + 2 \times \frac{\Delta v}{v} \] Where: - \( \Delta KE \) is the absolute error in kinetic energy, - \( KE \) is the kinetic energy, - \( \Delta m \) is the absolute error in mass, - \( m \) is the mass, - \( \Delta v \) is the absolute error in velocity, - \( v \) is the velocity. ### Step 4: Substitute the values into the formula Now, substituting the given percentage errors into the formula: \[ \frac{\Delta KE}{KE} = \frac{2}{100} + 2 \times \frac{1}{100} \] ### Step 5: Calculate the total percentage error Calculating the right-hand side: \[ \frac{\Delta KE}{KE} = \frac{2}{100} + \frac{2 \times 1}{100} = \frac{2}{100} + \frac{2}{100} = \frac{4}{100} \] Thus, the percentage error in kinetic energy is: \[ \frac{\Delta KE}{KE} \times 100 = 4\% \] ### Conclusion The percentage error in measuring the kinetic energy of the particle is **4%**. ---
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