The escape velocity of a body on the earth's surface is `v_e`. A body is thrown up with a speed `sqrt5``v_e` , Assuming that the sun and planet do not influlence the motion of the body , velocity of the bidy at infinite distance , is

Options

A. Zero
B. `V_e`
C. `sqrt2v_1`
D. `2V_e`

Answer

D

Explanation

Velocity of projection , V> Escape velocity, `V_e`
`therefore V^1 = (sqrtV^2 - V_e^2)= (sqrt(5v_e)^2- V_e^2)`= `sqrt(5v_e^2-v_e^2) = (2v_e)`