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The wavelength of two notes in air are 4...

The wavelength of two notes in air are `40/195 m` and `40/193 m`. Each note produces 9 beats per second separately with third note of fixed frequency. The velocity of sound in air in `m//s` is

A

360

B

320

C

300

D

340

Text Solution

Verified by Experts

The correct Answer is:
A

Beat frequency of two waves is given by, `V_(beat)=V_1-V_2`
`V_(beat)=V/((40/195))-V/((40/193))`
`9+9=(195V)/40-(193V)/40`
`18=(195V-193V)/40`
`V=360 m//s`
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