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When sound wave of wavelength lambda is ...

When sound wave of wavelength `lambda` is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is

A

`lambda`

B

`lambda/2`

C

`lambda/(2pi)`

D

`lambda/(4pi)`

Text Solution

Verified by Experts

The correct Answer is:
C
`V_(max)="Velocity"`
`Axx2piv= vlambda`
`A=lambda/(2pi)`
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