A segment of wire vibrates with a fundamental frequency of 450 Hz under a tension of 9Kg-wt.Then, tension at which the fundamental frequency of the same wire becomes 900 Hz is

Options

A. `36 Kg-wt`
B. `27 Kg-wt`
C. `18 Kg-wt`
D. `72 Kg-wt`

Answer

A

Explanation

Fundamental frequency of wire is given by,
`f=1/(2pi)sqrt(T/m)`
`(f_2/f_1 )=(1/(2pi)sqrt(T_2/m))/(1/(2pi)sqrt(T_1/m))`
`implies (f_2/f_1 )=sqrt(T_2/T_1`
`implies900/450=sqrt(T_2/9)`
`implies4=T_2/9`
`:. T_2=36kg-wt`