A transverse wave propagating on a stretched string of linear density `3xx10^-4 kg-m^-1` is represented by the equation
`y=0.2sin(1.5x+60t)`
Where x is in metre and t is in second. The tension in the string (in Newton) is

Options

A. 0.24
B. 0.48
C. 1.2
D. 1.8

Answer

B

Explanation

Comparing, `y=0.2sin(1.5x+60t)` with `y=Asin(kx+omegat)`,
`implies omega =60,k=1.5`
velocity of wave in stretched string
`V=sqrt(T/m),V=omega/k`
`implies omega/k=sqrt(T/m)`
`implies 60/1.5=sqrt(T/(3xx10^-4)) implies (40)^2=T/(3xx10^-4)`
`:. T=0.48N`