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If vibrating tuning fork of frequency 25...

If vibrating tuning fork of frequency 255Hz is moving with a velocity `4ms^-1` towards the wall the number of beats heard per second is (speed of sound in air = `340ms^-1`).

A

3

B

4

C

5

D

6

Text Solution

Verified by Experts

The correct Answer is:
A

Apparent frequency ,`n'=n(v/(v-v_s))`
`v=340ms^-1` and `v_s=4ms^-1` ,n = 255
`implies n'=255xx(340/(340-4))`
`implies n'= 258 "Hz"`
Number of beats heard =258-255=3
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