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The source and an observer move away fro...

The source and an observer move away from each other, each with a velocity of `10m//s`, with respect to ground, If the obsever find the frequency of sound coming from the source as 1950Hz, the original frequency of the source is (assume velocity of sound in air =`340ms^-1`)

A

1950 Hz

B

2068 Hz

C

1832 Hz

D

2186 Hz

Text Solution

Verified by Experts

The correct Answer is:
B
The apperent frequency when source and observer moving away from other, `n'=(v-v_0)/(v+v_0)xxn`
`n'=1950Hz,v_s=v_0=10ms^-1,v=340ms^-1`
`1950=((340-10)/(340+10))xxn`
`n=(1950xx350)/330=2068Hz`
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