A wave is given by the equation
`y=A sin 2pi ("f"t-x//lambda)`
Its maximum particle velocity is four times the wave velocity, when `lambda` is

Options

A. `piA`
B. `piA//2`
C. `piA//4`
D. `piA//8`

Answer

B

Explanation

Equation of wave,`y=Asin2x(ft-x/lambda)`
`y=Asin2x[1/lambda(flambdat-x)]`
`y=Asin((2x)/lambda)(ftlambda-x)`
`v=flambda`
`implies y=Asin((2pi)/lambda)(vt-x)`
maximum particle velocity ,`v_p=2pifA`
since `v_p=4v`
`2pifA=4flambda`
`lambda=(piA)/2`