A closed pipe 1 m long, emitting its second overtone, is in unison with an open pipe emitting its third overtone. The length of the open pipe will be

Options

A. 1.2m
B. 1.6m
C. 2.5m
D. 3.2m

Answer

B

Explanation

Frequency of second overtone for closed pipe ,`n_1=(5v)/(4l_1)` Frequency of third overtone for open pipe,`n_1=(4v)/(4l_2)`
Since, `n_1=n_2 ` and `l_1=1m`
`implies (5v)/(4l_1)=(4v)/(2l_2)`
`l_2=(4xx4xx1)/(5xx2)=1.6m`