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[" From the following molar conductiviti...

[" From the following molar conductivities at infinite dilution,"],[n_(m)^(0)" for Ba "(OH)_(2)=457.6Omega^(-1)cm^(2)mol^(-1)],[n_(m)^(0)" for "BaCl_(2)=240.6Omega^(-1)cm^(2)mol^(-1)],[Nm" for "NH_(4)Cl=129.8Omega^(-1)cm^(2)mol^(-1)],[" Calculate "^^_(m)^(0)" for "NH_(4)OH.]

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From the following molar conductivities at infinite dilution : wedge_(m)^(@) for Ba(OH)_(2)=457.6Omega^(1)cm^(2)mol^(-1) wedge_(m)^(@) for BaCl_(2)=240.6Omega^(-1) cm^(2)mol^(-1) wedge_(m)^(@) for NH_(4)Cl=129.8 Omega^(-1) cm^(2) mol^(-1) Calculate wedge_(m)^(@) for NH_(4)OH .

From the following molar conductivities at infinite dilution : wedge_(m)^(@) for Ba(OH)_(2)=457.6Omega^(1)cm^(2)mol^(-1) wedge_(m)^(@) for BaCl_(2)=240.6Omega^(-1) cm^(2)mol^(-1) wedge_(m)^(@) for NH_(4)Cl=129.8 Omega^(-1) cm^(2) mol^(-1) Calculate wedge_(m)^(@) for NH_(4)OH .

From the following molar conductivities at infinite dilution : wedge_(m)^(@) for Ba(OH)_(2)=457.6Omega^(1)cm^(2)mol^(-1) wedge_(m)^(@) for BaCl_(2)=240.6Omega^(-1) cm^(2)mol^(-1) wedge_(m)^(@) for NH_(4)Cl=129.8 Omega^(-1) cm^(2) mol^(-1) Calculate wedge_(m)^(@) for NH_(4)OH .

From the following molar conductivities at infinite dilution lamda_(m)^(@) for Ba(OH)_(2)=457.6ohm^(-1)cm^(2)mol^(-1) lamda_(m)^(@) for BaCl_(2)=240.6ohm^(-1)cm^(2)mol^(-1) lamda_(m)^(@) for NH_(4)Cl=129.8ohm^(-1)cm^(2)mol^(-1) Calculate lamda_(m)^(@) for NH_(4)OH

From the following molar conductivities at infinite dilution. Lambda_(m)^(@) for Ba(OH)_(2) = 457.6 Omega^(-1) cm^(2) "mol"^(-1) Lambda_(m)^(@) for BaCl_(2) = 240.6 Omega^(-1) cm^(2) "mol"^(-1) Lambda_(m)^(@) for NH_(4) Cl = 129.8 Omega^(-1) cm^(2) "mol"^(-1) Calculate Lambda_(m)^(@) for NH_(4) OH .

From the following molar conductivities at infinite dilution, Lamda_(m)^(@) " for " Al_(2) (SO_(4))_(3) = 858 S cm^(2) mol^(-1) Lamda_(m)^(@) " for " NH_(4)OH = 238.3 S cm^(2) mol^(-1) Lamda_(m)^(@) " for " (NH_(4))_(2)SO_(4) = 238.4 S cm^(2) mol^(-1) Calculate Lamda_(m)^(@) " for " Al(OH)_(3)

From the following molar conductivities at infinite dilution, Lamda_(m)^(@) " for " Al_(2) (SO_(4))_(3) = 858 S cm^(2) mol^(-1) Lamda_(m)^(@) " for " NH_(4)OH = 238.3 S cm^(2) mol^(-1) Lamda_(m)^(@) " for " (NH_(4))_(2)SO_(4) = 238.4 S cm^(2) mol^(-1) Calculate Lamda_(m)^(@) " for " Al(OH)_(3)

Calculate Lambda_(m)^(oo) for acetic acid, given, Lambda_(m)^(oo)(HCl)=426 Omega^(-1)cm^(2)mol^(-1),Lambda_(m)^(oo)(NaCl)=126Omega^(-1)cm^(2)mol^(-1) , Lambda_(m)^(oo)(CHCOONa)=91Omega^(-1)cm^(2)mol^(-1)