Electronic configuration of some elements is given in Column I and their electron gain enthalpies are given in column-II. Match the electronic configuration with electron gain enthalpy.

Answer

A

Explanation

(A`to`4), (B`to`1), (C`to`2), (D`to`3)
A) This electronic configuration corresponds to the noble gas i.e. neon. Since, noble gases have `+Delta_(eg)H` values, therefore configuration (A) corresponds to the `Delta_(eg)H = +48kJ mol^(-1)`.
B) This electronic configuration corresponds to the alkali metal, i.e, potassium. Alkali metals have small negative `Delta_(eg)H` values, hence, electronic configuration (B) corresponds to `Delta_(eg)=-53 kJ mol^(-1)`
C) This electronic configuration corresponds to the halogen i.e, fluorine. Since, halogens have high negative `Delta_(eg)H` values, therefore, electronic configuration (C) corresponds to `Delta_(eg)=H=328 kJ mol^(-1)`.
D) This electronic configuration corresponds to the electron i.e., oxygen. Since, chalcogens have `Delta_(eg)H` values less negative than those of halogens, therefore, electronic configuration (D) corresponds to `Delta_(eg)H=-141kJmol^(-1)`.