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It is known that x+y=10 and that x=z. S...

It is known that `x+y=10` and that `x=z`. Show that `z+y=10`.

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To solve the problem, we need to show that if \( x + y = 10 \) and \( x = z \), then \( z + y = 10 \). **Step 1: Start with the given equations.** We know: 1. \( x + y = 10 \) (Equation 1) 2. \( x = z \) (Equation 2) **Step 2: Substitute \( z \) for \( x \) in Equation 1.** ...
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Knowledge Check

  • It is known that if x+y=10 , then x+y+z=10+z . The Euclid's axiom that illustrates this statement is

    A
    first axiom
    B
    second axiom
    C
    third axiom
    D
    fourth axiom

  • Read the information given below and answer the questions that follow : The following functions have been defined : la(x, y, z) ="min" (x+y, y+z) "le" (x,y,z) ="max" (x-y, y-z) ma (x,y,z) =(1//2) ["le"(x,y,z) +la (x,y,z)] What is the value of ma (10, 4, le (la (10, 5, 3), 5, 3)) ?

    A
    `7.0`
    B
    6.5
    C
    `8.0`
    D
    7.5

  • The number of solutions of the equation x+y+z =10 in positive integers x,y,z is equal to

    A
    `36`
    B
    `55`
    C
    `72`
    D
    `45`

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