Ethylene cghloride and ethylidene chloride are isomers. Identify the correct statements.

Options

A. Both the compounds form same product on treatment wih alcoholic KOH
B. Both the compounds form same product on treatment with aq. NaOH
C. Both the compounds form same product on reduction
D. Both the compounds are optically active

Answer

A, C

Explanation

(A) Ethylene chloride and ethylidene chloride on treatment with alc. KOH show elimination reaction and ethyne as the product.

`underset("Ethylidene chloride")(CH_(3)-CHCl_(2))underset(("excess"))overset(Alc. KOH)toCHequivCH`
(b) Both these compounds from different products on treatment with aq. NaOH.
`Cl-CH_(2)-CH_(2)Clunderset(NaOH)overset(Aq.)toHO-underset("Ethylene glycol")(CH_(2)-CH_(2))-OH`
`CH_(3)-CHCl_(2)underset(NaOH)overset(Aq.)toCH_(3)-CH(OH)_(2)underset(-H_(2)O)tounderset("Ethanal")CH_(3)CHO`
(c) Both these compounds form same products on reduction.
`Cl-CH_(2)-CH_(2)-Cloverset("Reduction")tounderset("Ethane")(H_(3)C)-CH_(3)+2HCl`
`CH_(3)-CHCl_(2)tounderset("Ethane")(H_(3)C)-CH_(3)+2HCl`
(d) Both these compounds are optically inactive.