The unit of ebillioscopic constant is

Options

A. K kg `mol^(-1) or ("molality")^(-1)`
B. mol kg `K^(-1)or K^(-1)("molality")`
C. kg `mol^(-1)K^(-1)or K^(-1)("molality")^(-1)`
D. K `mol kg^(-1)or K ("molality")`

Answer

A

Explanation

As we know from elevation in boiling point that
`DeltaT_(b)K_(b)m`
`K_(b)=(DeltaT_(b))/(m)`
Unit of `K_(b)=("unit of "DeltaT_(b))/("unit of"m)=(K)/("molality")`
`=(K)/(molkg^(1))=Kmol^(-1)kg`