White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

Explanation

Equations for the reactions
`(P_(4)+6Cl_(2)to4PCl_(3)PCl_(3) (PCl_(3)+3H_(2)OtoH_(3)PO_(3)+3HCl]xx4)/(underset(31xx4=124g)underset("1 mol")(P_(4))+6Cl_(2)+12H_(2)Oto4H_(3)PO_(3)+underset(12xx36.5=438.0g)underset("12mol")(12HCl)`
`:'` 124 g of white phosphorus produces HCl `=438`g
`:.` 62 g of white phosphorus will produces
`HCl=(438)/(124)xx62=219.0g HCl`