A gas mixture consists of molecules of A,B and C with masses `m_(A) gt m_(B) gt m_(C).` Rank the three types of molecules in decreasing order of (a) average KE (b) rms speeds.

Explanation

The average KE will be the same , as conditions of temperature and pressure are the same.
`"Now as "" "V_("rms") =sqrt((3pV)/(M)) =sqrt((3RT)/(M))`
`=sqrt((3RT)/(mN)) =sqrt((3kT)/(m))`
`"where"" " m = "molar mass of the gas"`
m = mass of each molecular of the gas
R = gas constnat
`"Clearly"" "V_("rms") prop sqrt((1)/(m))`
(b). As K= Botlzmann constant
T= absolute temperature (same for all)
`"But"" "m_(A) gt m_(B) gt m_(c)`
`(V_("rms"))_(A) lt (V_("rms"))_(B) lt (V_("rms"))_(C)`
`:. " or " " "(V_("rms"))_(C) gt (V_("rms"))_(B) gt(V_("rms"))_(A)`