Calculate the number of degrees of freedom of molecules of hydrogen in 1cc of hydrogen gas at NTP.

Explanation

As given molecules are of hydrogen.
`:.` Volume occuipied by 1 mole
=1 mole of the gas at NTP
=22400 mL =22400cc
`:.` Number of molecules in 1 cc of hydrogen
`=(6.023 xx 10^(23))/(22400) = 2.688 xx 10^(19)`
`H_(2)` is a diatomic gas , having a total of 5 degrees of freedom (3 translation +2 rotational)
`:.` Total degrees of freedom possesed by all the molecules
`=5xx 2.688 xx 10^(19)`
`-=1.344 xx 10^(20)`
Note Any ideal gas has a molar volume of 22400 mL (cc) at NTP.