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If -3x+17 lt -13, then...

If `-3x+17 lt -13`, then

A

`x in (10, infty)`

B

`x in [10, infty)`

C

`x in (-infty, 10]`

D

`x in [-10, 10)`

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The correct Answer is:
To solve the inequality \(-3x + 17 < -13\), we can follow these steps: ### Step 1: Isolate the term with \(x\) We start with the inequality: \[ -3x + 17 < -13 \] Subtract \(17\) from both sides: \[ -3x < -13 - 17 \] ### Step 2: Simplify the right side Now, simplify the right side: \[ -3x < -30 \] ### Step 3: Divide by \(-3\) Next, we divide both sides by \(-3\). Remember that when we divide or multiply both sides of an inequality by a negative number, we must flip the inequality sign: \[ x > 10 \] ### Step 4: Write the solution in interval notation The solution \(x > 10\) can be expressed in interval notation as: \[ (10, \infty) \] ### Final Answer Thus, the solution to the inequality \(-3x + 17 < -13\) is: \[ x > 10 \quad \text{or} \quad x \in (10, \infty) \] ---

To solve the inequality \(-3x + 17 < -13\), we can follow these steps: ### Step 1: Isolate the term with \(x\) We start with the inequality: \[ -3x + 17 < -13 \] Subtract \(17\) from both sides: ...
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