If AOB is a diameter of a circle and C is a point on the circle, then `AC^(2)+BC^(2)=AB^(2)`.
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Since, any diameter of the circle subtends a right angle to any point on the circle. If AOB is a diameter of a circle and C is a point on the circle, then `DeltaACB` is right angled atC. In right angled `DeltaACB`, [use Pythagoras theorem] `AC^(2)+BC^(2)=AB^(2)`
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