Rms value of the saw-tooth voltage of peak value `V_(0)` as shown in-

Options

A. `(V_(0))/(2)`
B. `(V_(0))/(sqrt(2))`
C. `(V_(0))/(3)`
D. `(V_(0))/(sqrt(3))`

Answer

D

Explanation

`V(t) = -V_(0) + (2V_(0))/(T) xx t`
`V_(rms)= sqrt((overset(T)underset(0)int V^(2)dt)/(overset(T)underset(0)intdt)) = sqrt((overset(T)underset(0)int(V_(0)^(2)+(4V_(0)^(2)t^(2))/(T^(2))-(4V_(0)^(2)T)/(T))dt)/(overset(T)underset(0)intdt)`
`sqrt(((V_(0)^(2)T+(4V_(0)^(2)T)/(3)-2V_(0)^(2)T))/(T) = (V_(0))/(sqrt(3))`