(a) Calculate the relative molecular mass of water `(H_(2)O)`. (b) Calculate the molecular mass of `HNO_(3)`.
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(a) Atomic mass of hydrogen = 1u, oxygen = 16 u So the molecular mass of water, which contains two atoms of hydrogen and one atom of oxygen is = 2 × 1+ 1×16 = 18 u (b) The molecular mass of `HNO_(3)` = the atomic mass of H + the atomic mass of N+ 3 × the atomic mass of O = 1 + 14 + 48 = 63 u
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