Find out the hybridisation state of carbon atoms in given compounds from left to right.
`CH_(3) - CH = CH - CH = C = CH - C -= C - CH_(3)`

Options

A. `sp^(3)sp^(2)sp^(2)sp^(2)sp sp^(2) sp sp sp^(3)`
B. `sp^(3)sp^(2)sp^(2)sp sp sp spsp sp^(3)`
C. `sp^(3)sp^(2)sp^(2)sp^(2)sp^(2)sp^(2)sp sp sp^(3)`
D. `sp^(3) sp sp sp^(2) sp sp^(2) sp sp sp^(3)`

Answer

To determine the hybridization state of the carbon atoms in the compound `CH3 - CH = CH - CH = C = CH - C ≡ C - CH3`, we will analyze each carbon atom from left to right.

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound can be represented as follows:
```
CH3 - CH = CH - CH = C = CH - C ≡ C - CH3
```
We have a total of 9 carbon atoms in the structure.

2. **Count Sigma Bonds for Each Carbon**:
We will count the number of sigma (σ) bonds for each carbon atom, as the hybridization can be determined based on the number of sigma bonds.

- **Carbon 1 (C1)**:
- Bonds: 3 (from CH3) + 1 (to C2) = 4 sigma bonds
- Hybridization: **sp³**

- **Carbon 2 (C2)**:
- Bonds: 1 (to C1) + 1 (to C3) + 1 (from double bond with C3) = 3 sigma bonds
- Hybridization: **sp²**

- **Carbon 3 (C3)**:
- Bonds: 1 (to C2) + 1 (to C4) + 1 (from double bond with C2) = 3 sigma bonds
- Hybridization: **sp²**

- **Carbon 4 (C4)**:
- Bonds: 1 (to C3) + 1 (to C5) + 1 (from double bond with C5) = 3 sigma bonds
- Hybridization: **sp²**

- **Carbon 5 (C5)**:
- Bonds: 1 (to C4) + 1 (to C6) + 1 (from double bond with C4) = 3 sigma bonds
- Hybridization: **sp²**

- **Carbon 6 (C6)**:
- Bonds: 1 (to C5) + 1 (to C7) + 1 (from double bond with C7) = 3 sigma bonds
- Hybridization: **sp²**

- **Carbon 7 (C7)**:
- Bonds: 1 (to C6) + 1 (to C8) + 1 (from triple bond with C8) = 2 sigma bonds
- Hybridization: **sp**

- **Carbon 8 (C8)**:
- Bonds: 1 (to C7) + 1 (to C9) + 1 (from triple bond with C7) = 2 sigma bonds
- Hybridization: **sp**

- **Carbon 9 (C9)**:
- Bonds: 1 (to C8) + 1 (from CH3) = 2 sigma bonds
- Hybridization: **sp³**

3. **Summarize the Hybridization States**:
- C1: sp³
- C2: sp²
- C3: sp²
- C4: sp²
- C5: sp²
- C6: sp²
- C7: sp
- C8: sp
- C9: sp³

### Final Answer:
The hybridization states of the carbon atoms from left to right are:
- **C1: sp³**
- **C2: sp²**
- **C3: sp²**
- **C4: sp²**
- **C5: sp²**
- **C6: sp²**
- **C7: sp**
- **C8: sp**
- **C9: sp³**