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Arrange basicity of the given compounds ...

Arrange basicity of the given compounds in decreasing order -
`(a)CH_(3) - CH_(2) - NH_(2)" " (b)CH_(2) = CH - NH_(2)`
`(c) CH -= C - NH_(2)`

A

`a gt b gt c`

B

`a gt c gt b`

C

`c gt b gt a`

D

`b gt c gt a`

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The correct Answer is:
To arrange the basicity of the given compounds in decreasing order, we will analyze each compound based on the presence of lone pairs, resonance effects, and hybridization. ### Step-by-Step Solution: 1. **Identify the Compounds:** - (a) CH₃-CH₂-NH₂ (Ethylamine) - (b) CH₂=CH-NH₂ (Vinylamine) - (c) CH≡C-NH₂ (Propyne amine) 2. **Analyze Compound (a) CH₃-CH₂-NH₂:** - Ethylamine has an amine group (-NH₂) attached to a carbon chain. - The lone pairs on the nitrogen atom are localized and not involved in resonance. - This means that the basicity is high since the lone pair can readily accept a proton (H⁺). 3. **Analyze Compound (b) CH₂=CH-NH₂:** - Vinylamine has a double bond adjacent to the amine group. - The lone pair on the nitrogen can participate in resonance with the double bond. - This delocalization reduces the availability of the lone pair to accept a proton, thus decreasing its basicity compared to ethylamine. 4. **Analyze Compound (c) CH≡C-NH₂:** - Propyne amine has a triple bond adjacent to the amine group. - Similar to vinylamine, the lone pair on the nitrogen can also participate in resonance with the triple bond. - The hybridization of the nitrogen's adjacent carbon is sp, which means it has more s character (50%). - Higher s character in the hybridization of the adjacent carbon leads to decreased basicity because the lone pair is held closer to the nucleus. 5. **Compare Basicity:** - Since compound (a) has no resonance and the lone pair is localized, it is the most basic. - Between (b) and (c), (b) has less s character than (c) due to the sp² hybridization of the carbon in vinylamine (33% s character) compared to the sp hybridization in propyne amine (50% s character). - Therefore, the order of basicity is: - (a) CH₃-CH₂-NH₂ > (b) CH₂=CH-NH₂ > (c) CH≡C-NH₂ ### Final Arrangement: - **Basicity Order:** (a) > (b) > (c)
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