Statement-1: `Me - overset(o+)CH_(2)` is more stable than MeO `- CH_(2)^(o+)`
Statement-2: Me is a` +I` group where as MeO is a `–I` group.

Options

A. Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
B. Statement-1 is true, statement-2 is true and statement-2 is NOT correct explanation for statement-1.
C. Statement1 is false, statement-2 is true.
D. Statement1 is true, statement-2 is false.

Answer

To analyze the given statements, we will evaluate the stability of the carbocations mentioned in Statement-1 and the effects of the groups mentioned in Statement-2.

### Step-by-Step Solution:

1. **Understanding the Carbocations:**
- We have two carbocations to compare:
- **Me-CH2^+** (where Me = CH3)
- **MeO-CH2^+** (where MeO = CH3O)

2. **Evaluating the Stability of Me-CH2^+:**
- The **Me (methyl) group** is an electron-donating group due to its +I (positive inductive) effect. This means it can donate electron density to the positively charged carbon, stabilizing the carbocation.
- Therefore, the stability of **Me-CH2^+** is enhanced due to the +I effect of the methyl group.

3. **Evaluating the Stability of MeO-CH2^+:**
- The **MeO (methoxy) group** has a –I (negative inductive) effect due to the electronegativity of oxygen. This means it withdraws electron density from the positively charged carbon, which destabilizes the carbocation.
- However, the oxygen atom has lone pairs that can participate in resonance, providing some stabilization through resonance (mesomeric effect). This effect can sometimes outweigh the –I effect, but in this case, the overall effect is still destabilizing due to the strong –I effect.

4. **Comparison of the Two Carbocations:**
- Since the +I effect of the methyl group is stronger than the –I effect of the methoxy group, **Me-CH2^+** is more stable than **MeO-CH2^+**.
- Thus, Statement-1 is **false**.

5. **Analyzing Statement-2:**
- Statement-2 claims that Me is a +I group and MeO is a –I group.
- This is correct because the methyl group indeed has a +I effect, and the methoxy group exhibits a –I effect due to the electronegativity of oxygen.
- Therefore, Statement-2 is **true**.

### Conclusion:
- **Statement-1 is false**: Me-CH2^+ is more stable than MeO-CH2^+.
- **Statement-2 is true**: Me is a +I group, while MeO is a –I group.

### Final Answer:
- Statement-1: False
- Statement-2: True