What alkyl halide would yield each of the following pure alkene on reaction with alcoholic KOH ?
`CH_(3)-overset(CH_(3))overset(|)(C)=CH_(2)`

Explanation

To determine the alkyl halide that would yield the alkene \( CH_3-CH(CH_3)=CH_2 \) (2-methylpropene) upon reaction with alcoholic KOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Target Alkene**: The target alkene is 2-methylpropene, which has the structure \( CH_3-CH(CH_3)=CH_2 \). This indicates that the alkene has a double bond between the second and third carbon atoms, with a methyl group attached to the second carbon.

2. **Understand the Reaction Conditions**: The reaction involves alcoholic KOH, which acts as a strong base. In this context, it will facilitate an elimination reaction (dehydrohalogenation) to form the alkene from an alkyl halide.

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