Give the product of the following reaction.
`Me_(2)C=CH_(2)+IC1rarr`?

Explanation

To determine the product of the reaction between 2-methylpropene (Me₂C=CH₂) and iodine monochloride (I-Cl), we can follow these steps:

### Step 1: Identify the Reactants
The reactants are 2-methylpropene (Me₂C=CH₂) and iodine monochloride (I-Cl).

### Step 2: Understand the Electrophilic Addition Mechanism
In this reaction, the double bond in 2-methylpropene acts as a nucleophile and will react with the electrophile generated from I-Cl. Iodine (I) is less electronegative than chlorine (Cl), which means that I will act as the electrophile (I⁺) and Cl will act as the nucleophile (Cl⁻).

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