When 2-heptyne was treated with aq. `H_(2)SO_(4)` containing some `HgSO_(4)`, two products, each having the moleuclar formual `C_(7)H_(14)O`, were obtained approximately in equal amounts. What are these two compounds?

Explanation

To solve the problem, we need to identify the two products formed when 2-heptyne is treated with aqueous H₂SO₄ and HgSO₄. The process involves hydration of the alkyne, leading to the formation of alcohols. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Reactant
2-heptyne has the following structure:
```
CH₃-CH₂-CH₂-C≡C-CH₂-CH₃
```
This means it has a triple bond between the second and third carbon atoms in a seven-carbon chain.
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