Let `f (x) = x^(2) , x in [-1 , 2)` Then show that f(x) has exactly one point of local minima but global maximum is not defined.

Let f(x)= 2x^(3)-3(2+P)x^(2)+12Px+ln(16-P^(2)) .If f(x) has exactly one local minimum,one local maximum.Then the number of integral values of P is

Let f(x)=2x^(3)-3(2+p)x^(2)+12px+ln(16-p^(2)) If f(x) has exactly one local maxima and one local minima, then the number of integral values of p is

Let f(x)=2x^(3)-3(2+p)x^(2)+12px+ln(16-p^(2)) . If f(x) has exactly one local maxima and one local minima, then the number of integral values of p is

Let f(x)=2x^(3)-3(2+p)x^(2)+12px+ln(16) , f(x) has exactly one local maxima and one local minima, then the number of integral values of p is (are)

Let f(x)=2x^(3)-3(2+p)x^(2)+12px If f(x) has exactly one local maxima and one local minima, then the number of integral values of p is ....

Let f(x)=x^(3)-3x^(2)+6 find the point at which f(x) assumes local maximum and local minimum.

The function f(x)=(|x^(2)-2|)/(|x^(2)-4|) has,(a) no point of local maxima (b) no point of local minima (c) exactly one point of local minima (d) exactly one point of local maxima

Let f(x) be a function defined as follows: f(x)=sin(x^(2)-3x),x 0 Then at x=0,f(x) has a local maximum has a local minimum is discontinuous (d) none of these

Let f(x) be a polynomial of degree 3 having a local maximum at x=-1. If f(-1)=2,\ f(3)=18 , and f^(prime)(x) has a local minimum at x=0, then distance between (-1,\ 2)a n d\ (a ,\ f(a)), which are the points of local maximum and local minimum on the curve y=f(x) is 2sqrt(5) f(x) is a decreasing function for 1lt=xlt=2sqrt(5) f^(prime)(x) has a local maximum at x=2sqrt(5) f(x) has a local minimum at x=1