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A beaker of circular ceross sectionof ra...

A beaker of circular ceross sectionof radius 4 cm is filled with mercury up to a height of 10 cm. Find the force exerted by the mercury on the bottom of the beaker. The atmospheric pressure `=10^5Nm^-2`. Density of mercury `=13600 kgm^-3. Take g10ms^-2`

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The pressure at the surface=atmospheric presssure `=10^(5)" N"//m^(2)`.
The pressure at the bottom `10^(5)" N"//m^(2)+"h" rho g`
`=10^(5)" N"//m^(2)+(0.1" m")(13600("kg)/(m^(3)))(10(m)/(s^(2)))`
`=10^(5)" N"//m^(2)+13600" N"//m^(2)=1.136xx10^(5)" N"//m^(2)`
The force exerted by the mercury on the bottom
`=(1.136xx10^(5)"N"//m^(2))xx(3.14xx0.04" m"xx004" m")`
=571 N
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