Neglecting the density of air, the terminal velocity obtained by a raindrop of radius `0.3 mm` falling through the air of viscosity `1.8 xx10^(-5) N//m^(2)` will be

The terminal velocity of a rain drop is 30cm//s . If the viscosity of air is 1.8xx10^(-5)Nsm^(-2) .The radius of rain drop is

Calculate the viscous force on a liquid drop of radius 0.3 mm moving with a velocity of 5 cms^(-1) through a medium of viscosity 2 xx 10^(-5) Nm^(-2)s.

Find the terminal velocity of a rain drop of radius 0.01 mm. The coefficient of viscosity of air is 1.8xx10^-5 N-sm^-2 and its density is 1.2kgm^-3 .Density of water =1000kgm^-3 . Take g=10ms^-2

What is the terminal velocity of a copper ball of radius 2.0 mm, which falls through an oil tank? Given that density of oil = 1.5 xx 10^(3) kg m^(-3) , density of copper = 8.9 xx 10^(3) kg m^(-3) and viscosity of oil is 0.99 kg m^(-1)s^(-1) .

Find the terminal velocity acquired by a steel ball of diameter 3.2 mm falling under gravity through an oil of density 920 "kg m"^(-3) and viscosity 1.64"N s m"^(-2) . The density of steel may be taken as 7820 kg m^(-3) .

Calculate the terminal velocity of a water drop of radius 0.002 mm falling in air. Density of air =1.3" kg/m"^(3) . Density of water =10^3 "kg/m"^(3). Coefficient of viscosity of air is 1.7 xx 10^(-5)" decapoise."

The terminal velocity of a water drop of radius 0.01 mm falling through air is 1.12 cm/s. If the density of air is neglected, the coefficient of viscosity of air is [density of water =10^(3) kg//m^(3), g=9.8m//s^(2)]

Find the terminal velocity of solid sphere of radius 0.1 m moving in air in vertically downward direction. (eta=1.8xx10^(-5)(Ns)/(m^(2)) , density of sphere =1000(kg)/(m^(3)) and g=10(m)/(s^(2)))