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Electrostatic force experienced by - 3 m...

Electrostatic force experienced by `- 3 mu C` charge placed at point 'P' due to a system 'S' of fixed point charges as shown in figure is `vec(F) = (21 hat(i) + 9hat(j))mu N`.

If now `2 mu C` charge is placed and `-3 muC` is removed at point P then force experienced by it will be.

Text Solution

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Since the source charges are not disturbed the electric field intensity at 'P' will remain same.
`vec(F)_(2mu C) = +2 (vec(E))`
`= 2(-hat(i) - 3hat(j))`
`= 14hat(i) - 6hat(j) mu N`
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