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Six equal point charges are placed at th...

Six equal point charges are placed at the corners of a regular hexagon of side 'a'. Calculate electric field intensity at the centre of hexagon ?

Text Solution

Verified by Experts

Zero
Similarly electric field due to a uniformly charged ring at the centre of ring :
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Knowledge Check

  • Area of regular hexagon with side 'a' is

    A
    `(3sqrt(3))/(4) a^(2)` sq. unit
    B
    `(12)/(2sqrt(3)) a^(2)` sq. unit
    C
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    D
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  • Five identical point charges +Q are placed at the five corners of a regular hexagon of edge length a. One corner is empty. Electric field intensity at the centre of the hexagon is

    A
    Zero
    B
    `Q/(4piepsilon_0d^2)`, towards the empty corner
    C
    `Q/(4piepsilon_0d^2)`, away from the empty corner
    D
    `(5Q)/(4piepsilon_0a^2)` towards the empty corner

  • Five identical charge +q are placed at five corner of a regular hexagon of side a. Find the magnitude of electric field at centre.

    A
    `(1)/( 4pi epsilon_(0))(q)/(a^(2))`
    B
    `(q)/( 2pi epsilon_(0)a^(2))`
    C
    `( 5q)/( 4 pi epsilon_(0)a^(2))`
    D
    `(5q)/( 2pi epsilon_(0)a^(2))`

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