Find out following

(i) `V_(A)-V_(B)` (ii) `V_(B)-V_(C)` (iii) `V_(C)-V_(A)` (iv) `V_(D)-V_(C)`
(v) `V_(A)-V_(D)` (vi) Arrange the order of potential for points A, B, C and D.

Explanation

(i) `|Delta V_(AB)| = Ed = 20 xx 2 xx 10^(-2) = 0.4`
so, `V_(A) - V_(B) = 0.4 V`
because In the direction of electric field potential always decreases.
(ii) `|Delta V_(BC)| = Ed = 20 xx 2 xx 10^(-2) = 0.4`
so, `V_(B) - V_(C ) = 0.4 V`
(iii) `|Delta V_(CA)| = Ed = 20 xx 4 xx 10^(-2) = 0.8` so, `V_(C ) - V_(A) = -0.8 A`
because In the direction of electric field potential always decreases.
(iv) `|Delta V_(DC)| = Ed = 20 xx 0 = 0` so, `V_(D) - V_(C ) = 0`
because the effective distance between D and C is zero.
(v) `|Delta V_(AD)| = Ed = 20 xx 4 xx 10^(-2) = 0.8`, so, `V_(A) - V_(D) = 0.8 V`
because In the direction of electric field potential always decreases.
(vi) The order of potential `V_(A) gt V_(B) gt V_(C ) = V_(D)`.