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The two conducting spherical shells are ...

The two conducting spherical shells are joined by a conducting wire and cut after some time when charge stops flowing. Find out the charge on each sphere after that.

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After cutting the wire, the potential of both the shells is equal
Thus, potential of inner shell `V_("in")`
`= (kx)/(R ) + (K(-2Q - x))/(2R) = (k(x-2Q))/(2R)` and potential of outer shell `V_("out") = (Kx)/(2R) + (K(-2Q - x))/(2R) = (-KQ)/(R )`

As `V_("out") = V_("in") rArr (-KR)/(R ) = (K(x-2Q))/(2R)`
`rArr -2Q = x - 2Q rArr x = 0`
So charge on inner spherical shell = 0 and outer spherical shell = -2Q.
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