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A total charge Q is broken in two parts ...

A total charge `Q` is broken in two parts `Q_(1)` and `Q_(2)` and they are placed at a distance R from each other. The maximum force of repulsion between them will occur, when

A

`Q_(2) = (Q)/( R), Q_(1)=Q- (Q)/( R)`

B

`Q_(2) = (Q)/( 4), Q=Q- (2Q)/( 3)`

C

`Q_(2) = (Q)/( 4), Q_(1)= (3Q)/( 4)`

D

`Q_(1) = (Q)/( 2), Q_(2)= (Q)/( 2)`

Text Solution

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The correct Answer is:
D
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