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A force F is applied horizontally on mas...

A force F is applied horizontally on mass `m_(1)` as shown in figure. Find the contact force between `m_(1)` and `m_(2)`

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Considering both blocks as a system to find the common acceleration. Common acceleration
`a=(F)/((m_(1)+m_(2))` . . . . (1)

Fig. 1.18
To find the contact force between 'A' and 'B' we draw F.B.D. of mass `m_(2)`.
F.B.D. of mass `m_(2)`
`SigmaF_(x)=ma_(x)`
`N=m_(2).a`
`N=(m_(2)F)/((m_(1)+m_(2))`
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