A 5 kg block has a rope of mass 2 kg attached to its underside and a 3 kg block is suspended from the other end of the rope. The whole system is accelerated upward at `2m//s^(2)` by an external force `F_(0)`.

What is `F_(0)` ?
`(g=10m//s^(2))`

Explanation

For calculating the value of `F_(0)`, consider two blocks with the rope as a system.
F.B.D. of whole system

`F_(0)-100=10xx2`
`F=120N` . . . (1)