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When we jump out of a boat standing in w...

When we jump out of a boat standing in water it moves

A

forward

B

backward

C

side ways

D

none of these

Text Solution

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The correct Answer is:
B
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When the speed of a boat in still water is 4 km/h and the rate of stream is 2 km/h, find upstream speed of the boat

This summer we had gone to USA for a fun trip. For a change, we decided to take a motor boat along Niagra river. I hand heard a lot about Niagra water falls is 50 m high. What an adventure it would be to fall freely with the water fall. We started about 20 km upstream of the watyer fall with a motor boat which could travel at 18 km/hr relative to the water. the Biagra river is a slowly flowing river, flowing at pleasant 3.6 km/hr. The river is almost 300 m wide and we decided to go downstream with engine of motor boat on. Hardly we had gone 3-4 km when we noticed a long tree of length almost 10 m flowing 50 m away from us. our line of motion was passing through the centre of the tree which was oriented perpendicular to river flows. sensing our uneasiness, the boatman took a left turn by an angle theta (as seen by us) and we just managed to cross the tree. thereafter, the boat moved only downstreas as before. as we reached Niagra falls. the velocity of boat and the river was horizontal. the boat flew in the air and struck the water below at an angle to the horizontal. vow! That an experience of life. What was the distance between point of impact of boat and falling water ?

We know that when a boat travels in water, its net velocity w.r.t. ground is the vector sum of two velocities. First is the velocity of boat itself in river and other is the velocity of water w.r.t. ground. Mathematically: vecv_(boat) = vecv_(boat,water) + vecv_(water) . Now given that velocity of water w.r.t. ground in a river is u. Width of the river is d. A boat starting from rest aims perpendicular to the river with an acceleration of a = 5t, where t is time. The boat starts from point (1,0) of the coordinate system as shown in figure. Assume SI units.

We know that when a boat travels in water, its net velocity w.r.t. ground is the vector sum of two velocities. First is the velocity of boat itself in river and other is the velocity of water w.r.t. ground. Mathematically: vecv_(boat) = vecv_(boat,water) + vecv_(water) . Now given that velocity of water w.r.t. ground in a river is u. Width of the river is d. A boat starting from rest aims perpendicular to the river with an acceleration of a = 5t, where t is time. The boat starts from point (1,0) of the coordinate system as shown in figure. Assume SI units.

We know that when a boat travels in water, its net velocity w.r.t. ground is the vector sum of two velocities. First is the velocity of boat itself in river and other is the velocity of water w.r.t. ground. Mathematically: vecv_(boat) = vecv_(boat,water) + vecv_(water) . Now given that velocity of water w.r.t. ground in a river is u. Width of the river is d. A boat starting from rest aims perpendicular to the river with an acceleration of a = 5t, where t is time. The boat starts from point (1,0) of the coordinate system as shown in figure. Assume SI units.

If a man jumps out from a boat, the boat moves backwards. Why?

A man stands at one end of a boat which is stationary in water. Neglect water resistance. The man now moves to the other end of the boat and again becomes stationary. The centre of mass of the man plus boat system will remain stationary with respect to water.

MOTION-NEWTON'S LAWS OF MOTION & FRICTION -Exercise - 1 (SECTION-A:- String Constrained, Wedge Constrained, Newtons Law theory Question, Equillibrium Questions (Normal and Tension), Problems with Acceleration (F=ma), Wedge problems)
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  3. When we jump out of a boat standing in water it moves

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