A 63 gm bullet moving with velocity 200 m/s. Collides against a wall consequently two third of it's kinetic energy is converted into heat. Than what will be the heat developed by bullet in calorie. (Given : J = 4.2)

Explanation

To solve the problem step by step, we will calculate the kinetic energy of the bullet, determine the amount of energy converted to heat, and then convert that energy from joules to calories.

### Step 1: Calculate the Kinetic Energy (KE) of the bullet
The formula for kinetic energy is given by:

\[ KE = \frac{1}{2} m v^2 \]
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