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A carnot engine whose sink is at 290 K h...

A carnot engine whose sink is at 290 K has an efficiency of 30%. By how much the temperature of the source be increased to have its efficiency equal to 50%, keeping sink temperature constant

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To solve the problem step-by-step, we will use the efficiency formula for a Carnot engine and manipulate it to find the required temperature increase of the source. ### Step 1: Understand the Efficiency Formula The efficiency (η) of a Carnot engine is given by the formula: \[ \eta = 1 - \frac{T_L}{T_H} \] where: ...
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