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A carnot engine whose source temperature...

A carnot engine whose source temperature is at 400 K takes 100 kcal of heat at this temperature in each cycle and gives 70 kcal to the sink. Calculate (i) the temperature of the sink and (ii) the efficiency of the engine.

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To solve the problem step by step, we will find the temperature of the sink and the efficiency of the Carnot engine. ### Given Data: - Temperature of the source (Th) = 400 K - Heat absorbed from the source (Q1) = 100 kcal - Heat rejected to the sink (Q2) = 70 kcal ### Step 1: Calculate the Temperature of the Sink (Tl) ...
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