From the adjoining graph, the distance traversed by particle in 4 sec, is-

Options

A. 60 m
B. 25 m
C. 55 m
D. 30 m

Explanation

The given graph can be drawn as shown in figure Distance travelled = Area under v-t graph

= Area I + Area II + Area III + Area IV + Area V
`(1//2)(OH xx AH) + HG xx AH + 1//2 (G'C xx BG') + (GF xx GG') + EF xx CF )`
` = (1//2) (1xx 20) + (1 xx 20) + 1//2 (1 xx 10) + (1 xx 10) + (1 xx 10) = 10 + 20 + 5 + 10 + 10 = 55 m`
Hence correct answer is (C).