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A ball is thrown from ground vertically ...

A ball is thrown from ground vertically upward, reaches the roof of a house 100 meters high. At the moment this ball was thrown vertically upward, another ball is dropped from rest vertically downward from the roof of the house. At which height from the ground do the balls pass each other and after what time?

A

` t = (100)/(sqrt(1960)) ` sec , h = 25 m

B

` t = (100)/(sqrt(1690))` sec, h = 25 m

C

` t = (200)/(sqrt(1690))` , h = 75 m

D

`(100)/(sqrt(1960)) ` sec, h = 75 m

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the motion of both balls and find the height at which they meet and the time taken for that. ### Step 1: Understand the motion of both balls - **Ball 1** is thrown upwards from the ground. - **Ball 2** is dropped from the roof of the house (100 meters high). ### Step 2: Define the variables - Let \( h \) be the height from the ground where the balls meet. ...
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